本文實例為大家分享了python機器人行走步數問題,供大家參考,具體內容如下

#! /usr/bin/env python3
# -*- coding: utf-8 -*-
# fileName : robot_path.py
# author : zoujiameng@aliyun.com.cn
# 地上有一個m行和n列的方格。一個機器人從坐標0,0的格子開始移動,每一次只能向左,右,上,下四個方向移動一格,但是不能進入行坐標和列坐標的數位之和大于k的格子。
# 例如,當k為18時,機器人能夠進入方格(35,37),因為3+5+3+7 = 18。但是,它不能進入方格(35,38),因為3+5+3+8 = 19。請問該機器人能夠達到多少個格子?
class Robot:
# 共用接口,判斷是否超過K
def getDigitSum(self, num):
sumD = 0
while(num>0):
sumD+=num%10
num/=10
return int(sumD)
def PD_K(self, rows, cols, K):
sumK = self.getDigitSum(rows) + self.getDigitSum(cols)
if sumK > K:
return False
else:
return True
def PD_K1(self, i, j, k):
"確定該位置是否可以走,將復雜約束條件設定"
index = map(str,[i,j])
sum_ij = 0
for x in index:
for y in x:
sum_ij += int(y)
if sum_ij <= k:
return True
else:
return False
# 共用接口,打印遍歷的visited二維list
def printMatrix(self, matrix, r, c):
print("cur location(", r, ",", c, ")")
for x in matrix:
for y in x:
print(y, end=' ')
print()
#回溯法
def hasPath(self, threshold, rows, cols):
visited = [ [0 for j in range(cols)] for i in range(rows) ]
count = 0
startx = 0
starty = 0
#print(threshold, rows, cols, visited)
visited = self.findPath(threshold, rows, cols, visited, startx, starty, -1, -1)
for x in visited:
for y in x:
if( y == 1):
count+=1
print(visited)
return count
def findPath(self, threshold, rows, cols, visited, curx, cury, prex, prey):
if 0 <= curx < rows and 0 <= cury < cols and self.PD_K1(curx, cury, threshold) and visited[curx][cury] != 1: # 判斷當前點是否滿足條件
visited[curx][cury] = 1
self.printMatrix(visited, curx, cury)
prex = curx
prey = cury
if cury+1 < cols and self.PD_K1(curx, cury+1, threshold) and visited[curx][cury+1] != 1: # east
visited[curx][cury+1] = 1
return self.findPath(threshold, rows, cols, visited, curx, cury+1, prex, prey)
elif cury-1 >= 0 and self.PD_K1(curx, cury-1, threshold) and visited[curx][cury-1] != 1: # west
visited[curx][cury-1] = 1
return self.findPath(threshold, rows, cols, visited, curx, cury-1, prex, prey)
elif curx+1 < rows and self.PD_K1(curx+1, cury, threshold) and visited[curx+1][cury] != 1: # sourth
visited[curx+1][cury] = 1
return self.findPath(threshold, rows, cols, visited, curx+1, cury, prex, prey)
elif 0 <= curx-1 and self.PD_K1(curx-1, cury, threshold) and visited[curx-1][cury] != 1: # north
visited[curx-1][cury] = 1
return self.findPath(threshold, rows, cols, visited, curx-1, cury, prex, prey)
else: # 返回上一層,此處有問題
return visited#self.findPath(threshold, rows, cols, visited, curx, cury, prex, prey)
#回溯法2
def movingCount(self, threshold, rows, cols):
visited = [ [0 for j in range(cols)] for i in range(rows) ]
print(visited)
count = self.movingCountCore(threshold, rows, cols, 0, 0, visited);
print(visited)
return count
def movingCountCore(self, threshold, rows, cols, row, col, visited):
cc = 0
if(self.check(threshold, rows, cols, row, col, visited)):
visited[row][col] = 1
cc = 1 + self.movingCountCore(threshold, rows, cols, row+1, col,visited) + self.movingCountCore(threshold, rows, cols, row, col+1, visited) + self.movingCountCore(threshold, rows, cols, row-1, col, visited) + self.movingCountCore(threshold, rows, cols, row, col-1, visited)
return cc
def check(self, threshold, rows, cols, row, col, visited):
if( 0 <= row < rows and 0 <= col < cols and (self.getDigitSum(row)+self.getDigitSum(col)) <= threshold and visited[row][col] != 1):
return True;
return False
# 暴力法,直接用當前坐標和K比較
def force(self, rows, cols, k):
count = 0
for i in range(rows):
for j in range(cols):
if self.PD_K(i, j, k):
count+=1
return count
# 暴力法2, 用遞歸法來做
def block(self, r, c, k):
s = sum(map(int, str(r)+str(c)))
return s>k
def con_visited(self, rows, cols):
visited = [ [0 for j in range(cols)] for i in range(rows) ]
return visited
def traval(self, r, c, rows, cols, k, visited):
if not (0<=r<rows and 0<=c<cols):
return
if visited[r][c] != 0 or self.block(r, c, k):
visited[r][c] = -1
return
visited[r][c] = 1
global acc
acc+=1
self.traval(r+1, c, rows, cols, k, visited)
self.traval(r, c+1, rows, cols, k, visited)
self.traval(r-1, c, rows, cols, k, visited)
self.traval(r, c-1, rows, cols, k, visited)
return acc
if __name__ == "__main__":
# 調用測試
m = 3
n = 3
k = 1
o = Robot()
print(o.hasPath(k, m, n))
print(o.force(m,n,k))
global acc
acc = 0
print(o.traval(0, 0, m, n, k, o.con_visited(m,n)))
print(o.movingCount(k, m, n))
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