高斯變換,在C語(yǔ)言中實(shí)現(xiàn)的思路,知道的請(qǐng)告訴我,詳細(xì)點(diǎn)越好

#include stdio.h

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#include iostream.h

#include math.h

#includeiomanip.h

class Angle

{

public:

double degree,cent,second,Hudu,seconds;

//

構(gòu)造函數(shù)

Angle(double _degree,double _cent,double _second)

{

degree=_degree;

cent=_cent;

second=_second;

seconds=(degree*3600+cent*60+second);

Hudu=(degree*3600+cent*60+second)*2*3.1415926535/(360*60*60);

}

Angle()

{

}

SToD()

{

second=seconds-int(seconds/60)*60;

degree=int((seconds-second)/3600);

cent=int((seconds-second-degree*3600)/60);

}

~Angle()

{

}

};

void main()

{

//

正算過程

//

定義變量

Angle B(51,38,43.9023),L(126,2,13.1360),_B,_L;

double L0,l,N,a0,a4,a6,a3,a5,x,y,rou;

rou=(360*60*60)/(2*3.1415926535);

if(int(L.degree)%6!=0)

{

L0=6*(int(L.degree)/6+1)-3+6;

}

else

L0=6*(int(L.degree)/6)-3+6;

l=L.Hudu-L0*3600*2*3.1415926535/(360*60*60);

N=6399698.902-(21562.267-(108.973-0.612*cos(B.Hudu)*cos(B.Hudu))*cos(B.Hudu)*cos(

B.Hudu))*cos(B.Hudu)*cos(B.Hudu);

a0=32140.404-(135.3302-(0.7092-0.0040*cos(B.Hudu)*cos(B.Hudu))*cos(B.Hudu)*cos(B.

Hudu))*cos(B.Hudu)*cos(B.Hudu);

a4=(0.25+0.00252*cos(B.Hudu)*cos(B.Hudu))*cos(B.Hudu)*cos(B.Hudu)-0.04166;

a6=(0.166*cos(B.Hudu)*cos(B.Hudu)-0.084)*cos(B.Hudu)*cos(B.Hudu);

a3=(0.3333333+0.001123*cos(B.Hudu)*cos(B.Hudu))*cos(B.Hudu)*cos(B.Hudu)-0.166666

7;

a5=0.0083-(0.1667-(0.1968+0.0040*cos(B.Hudu)*cos(B.Hudu))*cos(B.Hudu)*cos(B.Hudu)

)*cos(B.Hudu)*cos(B.Hudu);

x=6367558.4969*B.Hudu-(a0-(0.5+(a4+a6*l*l)*l*l)*l*l*N)*sin(B.Hudu)*cos(B.Hudu);

y=(1+(a3+a5*l*l)*l*l)*l*N*cos(B.Hudu);

//結(jié)果輸出

cout"x="xendl;

cout"y="yendl;

// 反算過程

double b,Bf,Nf,Z,b2,b3,b4,b5,l1;

b=(x/6367558.4969);

Bf=b+(50221746+(293622+(2350+22*cos(b)*cos(b))*cos(b)*cos(b))*cos(b)*cos(b))*0.000

0000001*sin(b)*cos(b);

Nf=6399698.902-(21562.267-(108.973-0.612*cos(Bf)*cos(Bf))*cos(Bf)*cos(Bf))*cos(Bf)*c

os(Bf);

Z=y/(Nf*cos(Bf));

b2=(0.5+0.003369*cos(Bf)*cos(Bf))*sin(Bf)*cos(Bf);

b3=0.333333-(0.166667-0.001123*cos(Bf)*cos(Bf))*cos(Bf)*cos(Bf);

b4=0.25+(0.16161+0.00562*cos(Bf)*cos(Bf))*cos(Bf)*cos(Bf);

b5=0.2-(0.1667-0.0088*cos(Bf)*cos(Bf))*cos(Bf)*cos(Bf);

_B.seconds=Bf*rou-(1-(b4-0.12*Z*Z)*Z*Z)*Z*Z*b2*rou;

l1=(1-(b3-b5*Z*Z)*Z*Z)*Z*rou;

_L.seconds=L0*3600+l1;

_B.SToD();

_L.SToD();

請(qǐng)問如何用C語(yǔ)言編程編寫一個(gè)實(shí)現(xiàn)加法的函數(shù)，例如y=3x+1這個(gè)函數(shù)。

#include?stdio.h

double?f(double?x)

{return(x*3+1);}

void?main(){

double?x;

scanf("%lf",x);

printf("%lf",f(x));

}

C語(yǔ)言，我想通過調(diào)用口令函數(shù)和加法函數(shù)實(shí)現(xiàn)加法運(yùn)算

#includestdio.h

#includeconio.h

void?login();

void?add();

bool?flags?=?true;

void?main()

{

while(flags)

login();

//add();

//getch();

}

void?login()

{

int?k;

int?L=888;

printf("口令888;請(qǐng)輸入驗(yàn)證口令:");

scanf("%d",k);

if(L==k)

{

int?choice;

printf("您輸入正確,歡迎使用C計(jì)算器\n");

printf("+=======選擇要做的運(yùn)算=======+\n");

printf("+=?1、加法?=+\n");

printf("+=?2、減法?=+\n");

printf("+=?3、乘法?=+\n");

printf("+=?4、除法?=+\n");

printf("+=?5、求余?=+\n");

printf("+=?0、退出?=+\n?");

printf("+============================+\n");

scanf("%d",choice);

switch(choice)

{

case?1:

add();

break;

case?0:

flags?=?false;

break;

default?:?printf("您輸入有誤");

break;

}

}

else

{

printf("您輸入錯(cuò)誤,請(qǐng)重新輸入!");

}

}

void?add()

{

int?jia,fa;

printf("請(qǐng)輸入2個(gè)數(shù)");

scanf("%d?%d",jia,fa);

printf("%d+%d=%d\n",jia,fa,jia+fa);

}

首先你add寫在login里面，main先執(zhí)行l(wèi)ogin在執(zhí)行add，可是add在login了，所以main保留一個(gè)login，函數(shù)不能嵌套，add寫在外面。為了實(shí)現(xiàn)循環(huán)，添加一個(gè)標(biāo)志位flags初始為true，在選項(xiàng)里添加一個(gè)退出，選擇之后flags設(shè)為flase，退出計(jì)算器。

當(dāng)前題目：C語(yǔ)言用函數(shù)實(shí)現(xiàn)高斯加法 高斯求積公式c語(yǔ)言
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